Get Answers to all your Questions

header-bg qa

Q 1.8(b): Two point charges q_{A}=3\mu C and q_{B}=-3\mu C are located 20 cm apart in vacuum. If a negative test charge of magnitude1.5 \times 10^{-9}C is placed at this point, what is the force experienced by the test charge?

Answers (1)

best_answer

Let Q = -1.5 \times10^{-9} C

The force experienced by Q when placed at O due to the charges at A and B will be: 

F = Q \times E'

where E' is the net Electric field at the point O.

F=1.5 \times 10^{-9} C \times 5.4 \times 10^4 N/C = 8.1\times10^{-3 } N

Q being negatively charged will be attracted by positive charge at A and repelled by negative charge at B. Hence direction of force experienced by it will be in the direction of OA. 

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads