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# Use Hund’s rule to derive the electronic configuration of Ce3+ ion, and calculate its magnetic moment on the basis of ‘spin-only’ formula

8.31 Use Hund’s rule to derive the electronic configuration of $Ce^{3+}$ ion, and calculate its magnetic moment on the basis of ‘spin-only’ formula.

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Electronic configuration of $Ce= 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}4d^{10}5s^{2}5p^{6}4f^{1}5d^{1}6s^{2}$
Magnetic moment can be calculated as $\dpi{100} \mu = \sqrt{n(n+2)}$, where n= no. of unpaired electrons

in Cerium n = 2
So, by putting the value of n we get $\dpi{100} \mu = \sqrt{2(2+2)}= \sqrt{8}=2.828BM$

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