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8.13) Use the formula $\lambda _m T = 0.29 cm K$ to obtain the characteristic
temperature ranges for different parts of the electromagnetic
spectrum. What do the numbers that you obtain tell you?

Answers (1)

S Safeer PP

EM wave	one wavelength is taken from the range	Temperature $T=\frac{0.29}{\lambda}$
Radio	100 cm	$2.9\times 10^{-3}K$
Microwave	0.1cm	2.9 K
Infra-red	100000ncm	2900K
Light	50000 ncm	5800K
Ultraviolet	100ncm	$2.9\times10^{6}K$
X-rays	1 ncm	$2.9\times10^8K$
Gamma rays	0.01 nm	$2.9\times10^{10}K$

These numbers indicate the temperature ranges required for obtaining radiations in different parts of the spectrum

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