# 8.13) Use the formula $\lambda _m T = 0.29 cm K$ to obtain the characteristic temperature ranges for different parts of the electromagnetic spectrum. What do the numbers that you obtain tell you?

 EM wave one wavelength is taken from the range Temperature $T=\frac{0.29}{\lambda}$ Radio 100 cm $2.9\times 10^{-3}K$ Microwave 0.1cm 2.9 K Infra-red 100000ncm 2900K Light 50000 ncm 5800K Ultraviolet 100ncm $2.9\times10^{6}K$ X-rays 1 ncm $2.9\times10^8K$ Gamma rays 0.01 nm $2.9\times10^{10}K$