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# Use the formula lambda T is equal to 0.29 cmK to obtain the characteristic temperature ranges for different parts of the electromagnetic spectrum. What do the numbers that you obtain tell you?

8.13) Use the formula $\lambda _m T = 0.29 cm K$ to obtain the characteristic
temperature ranges for different parts of the electromagnetic
spectrum. What do the numbers that you obtain tell you?

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 EM wave one wavelength is taken from the range Temperature $T=\frac{0.29}{\lambda}$ Radio 100 cm $2.9\times 10^{-3}K$ Microwave 0.1cm 2.9 K Infra-red 100000ncm 2900K Light 50000 ncm 5800K Ultraviolet 100ncm $2.9\times10^{6}K$ X-rays 1 ncm $2.9\times10^8K$ Gamma rays 0.01 nm $2.9\times10^{10}K$

These numbers indicate the temperature ranges required for obtaining radiations in different parts of the spectrum

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