2.24 What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm? [You will realise from your answer why ordinary capacitors are in the range of \mu F or less. However, electrolytic capacitors do have a much larger capacitance (0.1 F) because of very minute separation between the conductors.]

Answers (1)

Given,

The capacitance of the parallel plate capacitor C=2F

Separation between plated d=0.5cm

Now, As we know

C=\frac{\epsilon _0A}{d}

A=\frac{Cd}{\epsilon _0}=\frac{2*5*10^{-3}}{8.85*10^{-12}}=1.13*10^9m^2

A=\1.13*10^3km^2=1130km^2

Hence, to  get Capacitance in Farads, the area of the plate should be of the order od kilometre which is not good practice, and so that is why ordinary capacitors are of range \mu F

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