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  • What is the force between two small charged spheres having charges of 2 × 10^–7 C and 3 × 10^–7 C placed 30 cm apart in air?

Q 1.1: What is the force between two small charged spheres having charges of 2 \times 10^{-7}C and 3 \times 10^{-7}C placed 30 cm apart in air?

Answers (1)

best_answer

Given,

q_{1} =  2 \times 10^{-7} C

q_{2} =  3 \times 10^{-7}C

r = 30 cm = 0.3 m 

We know,

Force between two charged particles, q_{1}  and q_{2} separated by a distance r.

F = \frac{1}{4\pi \epsilon _{0}} \frac{q_{1}q_{2}}{r^2}

= \frac{1}{4\pi \epsilon _{0}} \frac{2\times10^{-7} \times 3 \times 10^{-7}}{(30\times10^{-2}\ m)^2\ }

= (9\times10^9\ N)\times \frac{6\times10^{-14+4}}{900\ m^2\ } = 6\times10^{-3} N

Since, the charges are of same nature, the force is repulsive.

Posted by

HARSH KANKARIA

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