Q 1.1: What is the force between two small charged spheres having charges of 2 \times 10^{-7}C and 3 \times 10^{-7}C placed 30 cm apart in air?

Answers (1)

Given,

q_{1} =  2 \times 10^{-7} C

q_{2} =  3 \times 10^{-7}C

r = 30 cm = 0.3 m 

We know,

Force between two charged particles, q_{1}  and q_{2} separated by a distance r.

F = \frac{1}{4\pi \epsilon _{0}} \frac{q_{1}q_{2}}{r^2}

= \frac{1}{4\pi \epsilon _{0}} \frac{2\times10^{-7} \times 3 \times 10^{-7}}{(30\times10^{-2}\ m)^2\ }

= (9\times10^9\ N)\times \frac{6\times10^{-14+4}}{900\ m^2\ } = 6\times10^{-3} N

Since, the charges are of same nature, the force is repulsive.

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout JEE Main April 2022 (Subscription)

Knockout JEE Main April 2022 Subscription.

₹ 5499/-
Buy Now
Knockout NEET May 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 4999/-
Buy Now
Exams
Articles
Questions