8.5     What may be the stable oxidation state of the transition element with the following d electron configurations in the ground state of their atoms : 3d^{3}, 3d^{5}, 3d^{8} \; and\; 3d^{4} ?

Answers (1)

3d^{3} 
Vanadium (atomic number- 23)
E.C = [Ar]^{18}3d^{3}4s^{2},
So the stable oxidation states are (+2, +3, +4, +5)

 

3d^{5}
Manganese (atomic number = 25)
E.C = [Ar]^{18}3d^{5}4s^{2} ,
So the stable oxidation state are (+2, +4, +6, +7)

 

3d^{5}
chromium (atomic number = 24)
E.C = [Ar]^{18}3d^{5}4s^{1},
So the stable oxidation state are (+3, +4, +6)

 

3d^{4}
No elements has d^{4}  electronic configuration in their ground state.

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