8.5     What may be the stable oxidation state of the transition element with the following d electron configurations in the ground state of their atoms : 3d^{3}, 3d^{5}, 3d^{8} \; and\; 3d^{4} ?

Answers (1)
M manish

3d^{3} 
Vanadium (atomic number- 23)
E.C = [Ar]^{18}3d^{3}4s^{2},
So the stable oxidation states are (+2, +3, +4, +5)

 

3d^{5}
Manganese (atomic number = 25)
E.C = [Ar]^{18}3d^{5}4s^{2} ,
So the stable oxidation state are (+2, +4, +6, +7)

 

3d^{5}
chromium (atomic number = 24)
E.C = [Ar]^{18}3d^{5}4s^{1},
So the stable oxidation state are (+3, +4, +6)

 

3d^{4}
No elements has d^{4}  electronic configuration in their ground state.

Related Chapters

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions