# Q9.    Which of the given values of x and y make the following pair of matrices equal $\begin{bmatrix} 3x + 7 &5 \\ y + 1 & 2 -3x \end{bmatrix}$, $\begin{bmatrix} 0 & y - 2 \\ 8 & 4 \end{bmatrix}$        (A)    $x = \frac{-1}{3}, y = 7$        (B)    Not possible to find        (C)    $y =7, x = \frac{-2}{3}$        (D)    $x = \frac{-1}{3}, y = \frac{-2}{3}$

Given,     $\begin{bmatrix} 3x + 7 &5 \\ y + 1 & 2 -3x \end{bmatrix}$ $=\begin{bmatrix} 0 & y - 2 \\ 8 & 4 \end{bmatrix}$

If two matrices are equal, then their corresponding elements are also equal

$3x+7=0\Rightarrow x=\frac{-7}{3}$

$y-2=5 \Rightarrow y=5+2=7$

$y+1=8\Rightarrow y=8-1=7$

$2-3x=4\Rightarrow 3x=2-4\Rightarrow 3x=-2\Rightarrow x=\frac{-2}{3}$

Here, the value of x is not unique, so option B is correct.

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