Let physical quantity be a force
So $[\mathrm{F}]=M L T^{-2}$
If we replace $M, L, T$ in the dimensional formula of the physical quantity by fundamental units of the required system, we will get the unit of that physical quantity.
Now we want to find the unit of Force in SI system
Which is $k g m\left(\mathrm{sec}^{-2}\right)$ or Newton
| Exam | Chapter |
| JEE MAIN | Physics and Measurement |
CGS unit of Force is
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The quantities
are defined where C - capacitance, R - resistance, l - length, E - Electric field, B - magnetic field
- free space permittivity and permeability respectively, then:
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A quantity x is given by in terms of a moment of inertia I, force F, velocity v, work W and length L. The dimensional formula for the x is the same as that of:
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Match List I with List II.
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A. Torque |
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B. Stress |
II. |
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C. Latent Heat |
III. |
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D. Power |
IV. |
Choose the correct answer from the options given below:
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If velocity [V], time [T] and force [F] are chosen as the base quantities, the dimensions of the mass will be :
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In a typical combustion engine the workdone by a gas molecule is given by where x is the displacement, k is the Boltzmann constant and T is the temperature. If
and
are constants, dimensions of
will be :
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The truth table of the given circuit diagram is:

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Match List - I with List - II.
| List – I | List – II |
| (A) Coefficient of viscosity | (I) $\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^{-2}\right]$ |
| (B) Surface tension | (II) $\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^{-1}\right]$ |
| (C) Angular momentum | (III) $\left[\mathrm{M} \mathrm{L}^{-1} \mathrm{~T}^{-1}\right]$ |
| (D) Rotational kinetic energy | (IV) $\left[\mathrm{M} \mathrm{L}^0 \mathrm{~T}^{-2}\right]$ |
Choose the correct answer from the options given below :
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One Newton is equal to -
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The unit of work is -
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What is the dimensional formula of $a b^{-1}$ in the equation $\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}$, where letters have their usual meaning?
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