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If p and q are order and degree of differential equations y^2 (d2y/dx2)^2 +3x(dy /dx ) ^ 1/3 +x^2 y^2 = sin x . then

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Solution:   We have ,

                  y^2(fracmathrmd ^2ymathrmd x^2)^2+3x(fracmathrmd ymathrmd x)^frac13+x^2y^2=sin x

           Rightarrow         y^2(fracmathrmd ^2ymathrmd x^2)^2+x^2y^2-sin x=-3x(fracmathrmd ymathrmd x)^frac13

           	herefore           (y^2(fracmathrmd ^2ymathrmd x^2)+x^2y^2-sin x)=-27x^3(fracmathrmd ymathrmd x)

         Here order  =2=p    ,    degree=6=q

     

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Deependra Verma

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