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  • 1)FIND THE LEAST NUMBER BY WHICH 3528 SHOULD BE MULTIPLIED TO GET A PERFECT SQUARE.2)FIND THE LEAST NUMBER BY WHICH 5000 SHOULD BE DIVIDED TO GET A PERFECT CUBE.3)FIND THE LEAST NUMBER BY WHICH 180 SHOULD BE DIVIDED TO GET A PERFECT SQUARE.

1)FIND THE LEAST NUMBER BY WHICH 3528 SHOULD BE MULTIPLIED TO GET A PERFECT SQUARE.2)FIND THE LEAST NUMBER BY WHICH 5000 SHOULD BE DIVIDED TO GET A PERFECT CUBE.3)FIND THE LEAST NUMBER BY WHICH 180 SHOULD BE DIVIDED TO GET A PERFECT SQUARE.

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1);3528=2^3 imes 3^2 imes 7^2\*Now;we;know;that;a;perfect; square; should;have;a;pair;of;two;prime;factor.\* This;number; has;1;pair;of; 2,1;pair ;of;3,1;pair;of;7;and;1;alone;factor;2.\* Therefore,;this;number;has;a;2;less.\*So,;2;must;be;multiplied;in;3528;to;get;a; perfect;square.\* 2); 5000 = 2^3 imes 5^4\*Now;we;know;that;a;perfect;cube;should; have;a;pair;of;three;prime; factor.\*This;number;has;1;pair; of;2, 1;pair;of;5;and;1;alone;factor;5.\*Therefore,;this;number;has;a;5;more.\*So,;5;must; be;divided;in;5000;to; get;a;perfect;cube.\* 3); 180=2^2 imes 3^2 imes 5\* Now,;we;know ;that ;a; perfect; square ;should;have;a;pair;of;two;prime;factor.\* This; number ;has ;1;pair ;of ;2,1 ;pair; of ;3 ;and ;1;alone ;factor ;5.\* Therefore,;this;number; has ;a; 5; more.\* So,; 5 ;must ;be ;divided ;in ;180; to; get; a; perfect ;square.

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Deependra Verma

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