2 trees, A&B are on the same side of a river. From a point C in the river the distance of the trees A&Bis 250 m and 300 m ,respectively.if the the angle C is 45,find the between the trees?

Answers (1)

In Traingle ABC
LC=45,AC=250m,BC=300m
By applying the cosine rule
a^2=b^2+c^2-2bc, cos A
So
AB^2=AC^2+BC^2-2ACBCcos C
=250^2+300^2-2(250)(300)cos 45^circ
AB^2=46433.98
AB=sqrt46433.98
AB=215.5m

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