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2x+5y=1,x-3y=6 and x+5y+2=0 are concurrent

Answers (1)

Given that, 

2x+5y=1..........1
x-3y=6...............2
multiplying 2 equation by 2
2x-6y=12........3
subtracting 1 from 3
-11y=11
y=-1
then x = 3
to prove this line is concurrent it should satisfy other equation..
putting x=3 and y=-1
3-5+2=0
5-5=0
Proved

Hence the above lines are concurrent.

 

Posted by

Satyajeet Kumar

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