# A 200  parallel plate capacitor having plate separation of 5 mm is charged by a 100 V dc source. It remains connected to the source. Using an insulated handle, the distance between the plates is doubled and a dielectric slab of thickness 5 mm and dielectric constant 10 is introduced between the plates. Explain with reason, how the (i) capacitance, (ii) electric field between the plates, (iii) energy density of the capacitor will change?

The effective separation between the plates with air in between is

that is

(i)   new capacitance

(ii) change in the electric field or effective new electric field

(iii) Energy density

As C has decreased energy also decreases, so energy density also decreases.

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