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(a) Account for the following :

(i) Hydration enthalpy of F^{-} ion is more than Cl^{-} ion. 

(ii) SO_{2} is a reducing agent, whereas TeO_{2} is an oxidising agent in group-16 oxides.

(b) Write the reaction of F_{2} with water. Why does I_{2} not react with water ? 

(c) Draw the structure of XeF_{2}.

 

 
 
 
 
 

Answers (1)

a)

 i) Hydration enthalpy of F^{-} ion is more than Cl^{-} ion because of smaller size of F – ion than Cl– ion

 ii) SO_{2} is a reducing agent, whereas TeO_{2} is an oxidising agent in group-16 oxides because sulphur is more stable in +6 state and Tellurium is more stable in +4 state

b) 2F2 + 2H2O ------->  4HF + O2

 Idoesnot react with water because I2 is a weak oxidizing agent.

structure of XeF_{2}.

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Safeer PP

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