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  • (a) Account for the following:     (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +4.     (ii) <img alt="Cr^{2+}" src="https://entranceco

(a) Account for the following:

    (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +4.

    (ii) Cr^{2+} is strong reducing agent.

    (iii) Cu^{2+} salts are coloured while Zn^{2+} salts are white.

(b) Complete the following equations:

    (i) 2MnO_{2}+4KOH+O_{2}\overset{\Delta}{\rightarrow}

    (ii) Cr_{2}O_{7}^{2-}+14H^{+}+6I^{-}\rightarrow

 

 

 

 
 
 
 
 

Answers (1)

(a)

    (i) Mn shows the highest oxidation state of +7 with oxygen but with flourine it shows the highest oxidation state of +4 because of ability of oxygen to form multiple bonds with transction metals (d\pi -p\pi) but fluorine cannot do so.

    (ii) Cr^{2+} is a strong reducing agent, it very easily does electrons to achieve its highest oxidation state of +6 to becomes extra stable.

    (iii) Cu^{2+} salts are coloured whereas Zn^{2+} salts are white because Zn^{2+} does not have unpaired electrons, it has fully filled d-orbitals and unpaired electrons excite to give colour to compounds whereas Cu^{2+} salts have unpaired electrons.

(b)

    (i) 2MnO_{2}+4KOH+O_{2}\overset{\Delta}{\rightarrow}2K_{2}MNO_{4}+2H_{2}O

    (ii)  Cr_{2}O_{7}^{2-}+14H^{+}+6I^{-}\rightarrow 2Cr^{3+}+3I_{2}+7H_{2}O 

    

Posted by

Sumit Saini

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