Get Answers to all your Questions

header-bg qa

(a) Account for the following :
    (i)    Reducing character decreases from SO2 to TeO2.
   (ii)    HClO3 is a stronger acid than HClO.
  (iii)    Xenon forms compound with fluorine and oxygen only.

(b)    Complete the following equations :

            (i)    \mathrm{4NaCl + MnO_2 + 4H_2SO_4\rightarrow}

           (ii)    \mathrm{6XeF_4 + 12H_2O\rightarrow}

 

 

 

 
 
 
 
 

Answers (1)

(a)     (i)    Reducing character decreases from SO2 to TeO2 since down the group with an increase in the size of the central atom there is decrease electronegativity and metallic character increase.

       (ii)    HClO3 is a stringer acid than HClO since strength decrease with a decrease in oxidation number and the oxidation number of Cl in HClO3 is +5 whereas in HClO it is +1.

      (iii)    Xenon forms compound only with fluorine and oxygen because of high electronegativity, fluorine and oxygen are strong oxidizing agents.

(b)    (i)    \mathrm{4NaCl + MnO_2 +4H_2SO_4\rightarrow MnCl_2 + 4NaHSO_4 + 2H_2O + Cl_2}

       (ii)   

 \mathrm{6XeF_4 + 12H_2O \rightarrow 4Xe +2XeO_3 + 24HF + 3O_2}

Posted by

Sumit Saini

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads