(a) Although both \left [ NiCl_4 \right ]^{2-}\: and\: \left [ Ni\left ( CO \right )_4 \right ] have sp^{3} hybridisation yet \left [ NiCl_4 \right ]^{2-} is paramagnetic and \left [ Ni \right (CO)_4] is diamagnetic. Give reason. (Atomic no. of Ni = 28)

 

(b) Write the electronic configuration of d^{5} on the basis of crystal field theory when

(i) \Delta _{0}<P\: \: \: and

(ii) \Delta _{0}>P

 

 

 

 
 
 
 
 

Answers (1)

(a) Cl, being a weak ligand, does not pair up the electrons, so, \left [ NiCl_4 \right ]^{2-} is paramagnetic, while in \left [ Ni(CO)_4 \right ], CO, being a strong ligand pair up  the electrons as it approaches the metal ion, leaving no electrons unpaired, hence it is diamagnetic.

(b) (i) \Delta _{0}<P,\: \: \: t_{2}^{3}g\: eg^2

(ii) \Delta _{0}>P,\: \: \: t_{2}^{5}g

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