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A and B can do it piece of work in 14 days and 21 days respectively. They start work together but after 3 days A leave it. In How many days work will be finish?

Answers (1)

Work done by A in one day = 1/14 part of work.

Work done by B in one day = 1/21 part of work.

Work done by (A+B) in one day = 1/14 + 1/21 = 5/42 part of work

Work done by (A+B) in three days = 15/42 part of work

Remainimg work = 1 - 15/42 = 27/42 = 9/14 part of work

Now the remaining work 9/14 is done by B alone.

1/21 of work done by B = one day 

9/14  of work done by B = 9/14/(1/21) = 9x21/14 = 27/2 days = 13.5 days

Total time to complete this work = 13.5 + 3 = 16.5 days

Posted by

Ravindra Pindel

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