# A capacitor made of two parallel plates, each of area ‘A’ and separation 'd’ is charged by an external dc source. Show that during charging, the displacement current inside the capacitor is the same as the current charging the capacitor.

Total current

$i=i_{c}+i_{d}$

Where, $i_{c}$ is conduction current and

$i_{d}$ is displacement current

Outside the capacitor, the displacement current; $i_{d}=0$ so, $i=i_{c}$

Inside the capacitor, the conduction current;       $i_{c}=0$ So, $i=i_{d}$

Hence,

the displacement current is the same as the current charging the capacitor.

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