A certain n-p-n transistor has the common emitter output characteristics as shown in the figure.

(a) Find the emitter current atV_{CE} = 12.5 \: V \: and\: I_{b} = 60\: \mu A, and
(b) Current gain '\beta ' at this point.

 

 
 
 
 
 

Answers (1)
S safeer

We have given;

V_{CE}=12.5\: v

I_{b}=60\; \mu A

I_{c}=6\; mA\;   (from the given graph)

We know,

I_{e}=I_{b}+I_{c}

Where, I_{e} = emitter current

             I_{b} = base current

             I_{c} = Collector current

\therefore I_{e}=60\; \mu A+6\; mA

\therefore I_{e}=60\times 10^{-6}A+6\times 10^{-3}A

I_{e}= 6.060 \; mA

Calculating the current gain

(\beta )=\frac{I_{c}}{I_{b}}=\frac{6mA}{60\mu A}

\beta =\frac{6\times 10^{-3}}{6\times 10^{-6}}=\frac{6}{60}\times 10^{-3}\times 10^{6}

\beta = 0.1\times 10^{3}

\beta = 100

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