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A charged particle q is moving in the presence of a magnetic field B which is inclined to an angle 30° with the direction of the motion of the particle. Draw the trajectory followed by the particle in the presence of the field and explain how the particle describes this path.

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The force acting on a charged particle in a magnetic field is given by ; \vec{F}=q(\vec{V}\times \vec{B})

Where q = charge of the particle

              v = velocity of particle and

             B = magnetic field in that region

Let velocity has a component along with B, this component remains unchanged as the motion along the magnetic field will not be affected by the magnetic field.

The motion in a plane perpendicular to B is circular one, thereby producing a helical motion. Thus the described path will be helical as shown in the figure.

Posted by

Safeer PP

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