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(a) Classify the following six nuclides into (i) isotones, (ii) isotopes, and (iii) isobars :

        _{6}^{12}\textrm{C},\; _{2}^{3}\textrm{He},\; _{80}^{198}\textrm{Hg},\; _{1}^{3}\textrm{H},\; _{79}^{197}\textrm{Au},\; _{6}^{14}\textrm{C}

(b) How does the size of a nucleus depend on its mass number? Hence explain why the density of nuclear matter should be independent of the size of the nucleus.

 

 
 
 
 
 

Answers (1)

(a) Classification of nuclides are as follows;-

(i) isotopes\; ;\; _{6}^{12}\textrm{C}\; and\; _{6}^{14}\textrm{C}

(ii) isobars\; ;\; _{2}^{3}\textrm{He}\; and\; _{1}^{3}\textrm{H}

(iii) isotones\; ;\; _{80}^{198}\textrm{Hg}\; and\; _{79}^{197}\textrm{Au}

(c) The radius of the nucleus having mass number A is given as ;

        R=r_{0}(A)^{\frac{1}{3}}

Where, A= mass no.

            R= radius

            r_{0}= constant value

Such that, the volume of the nucleus;- 

=\frac{4}{3}\pi R^{3}

 =\frac{4}{3}\pi \times r_{0}^{3}\times A^{\frac{1}{3}\times 3}

 =\frac{4}{3}\pi r_{0}^{3} A

  If m be the average mass of a nucleon, then the mass of nucleus =mA

\therefore the nuclear density

=\frac{mass }{volume }=\frac{mA}{\frac{4}{3}\pi (r_{0}^{3})\times A}=\frac{3m}{4\pi (r_{0})^{3}}

Hence, nuclear density is independent of the size of the nucleus.

Posted by

Safeer PP

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