Solution: Let R and H are the base radius and height of large cone respectively .
So , its volume is
Now , the small cone that is generated
after dividing the large cone will have height H/2 and radius R/2
Therefore , its volume will be
So ,the frustum so generated will have Volume =
Therefore , the ratio of the volume of small cone and the frustum generated will be V/8:7V/8=1:7