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  • A crystalline solid ‘A’ burns in air to form a gas ‘B’ which turns lime water milky. The gas is also produced as a by-product during roasting of sulphide ore. This gas decolourises acidified  <img alt="K\!MnO_4" src="h

A crystalline solid ‘A’ burns in air to form a gas ‘B’ which turns lime water milky. The gas is also produced as a by-product during roasting of sulphide ore. This gas decolourises acidified  K\!MnO_4 (aq.)  solution and reduces  Fe^{3+} to  Fe^{2+}. Identify ‘A’ and ‘B’ and write the reactions involved.

 

 

 

 
 
 
 
 

Answers (1)

A (solid) burns in air  \rightarrow B (gas)

B decolourises K\!MnO_4

turns lime water milky and reduces Fe^{3+}\rightarrow Fe^{2+}

\therefore A=S_8;B=SO_2

 1.\: S_8+8O_2\rightarrow 8SO_2

2.\: 5SO_2+2MnO_4^-+2H_2O\rightarrow 5SO_4^{2-}+2Mn^{2+}+4H^+

3.\: SO_2+2Fe^{3+}+2H_2O\rightarrow 2Fe^{2+}+SO_4^{2-}+4H^+

4.  By product of roasting of sulphide ore

FeS_2+11O_2\rightarrow 2Fe_2O_3+8SO_2

 

Posted by

Sumit Saini

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