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  • (a) Derive the expression for the torque acting on the rectangular current carrying coil of a galvanometer. Why is the magnetic field made radial ? (b) An -parti

(a) Derive the expression for the torque acting on the rectangular current carrying coil of a galvanometer. Why is the magnetic field
made radial ?
(b) An \alpha-particle is accelerated through a potential difference of 10\; kV and moves along x-axis. It enters in a region of uniform magnetic field B=2\times 10^{-3}T acting along y-axis. Find the radius of its path. (Take mass of \alpha-particle =6.4\times 10^{-27}kg )

 

 

 

 
 
 
 
 

Answers (1)

Let us consider a loop ABCD in a uniform magnetic field of strength B. and Let the current through the loop be I.

Magnetic forces of AB and CD are equal and opposite and have
a different line of action so constitutes torque.

\tau=F\timesthe perpendicular distance between two force arm
\tau=Bilbsin\theta
lb=A
\tau=BiAsin\theta

Radial fields always produce maximum torque

The radius of the circular path

r=\frac{1}{B}\sqrt{\frac{2mV}{q}}

=\frac{1}{2\times10^{-3}}\sqrt{\frac{2\times6.4\times10^{-27}\times10\times10^3}{2\times1.6\times10^{-19}}}=10m

 

Posted by

Safeer PP

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