(a) Draw structure and name the shape of the following:

        (i) SF_{4}

         (ii)    ICl_{3}

(b) What happens when (support your answer with equation)

    (i) Chlorine gas is passed through hot and concentrated sodium hydroxide solution?

    (ii) Xenon hexafluoride is subjected to complete hydrolysis?

   (iii) Concentrated sulphuric acid is poured over cane sugar?

 

 

 

 
 
 
 
 

Answers (1)
S Sumit

(a) (i) SF_{4}

        

        (ii) ICl_{3}

           

(b) (i) Chlorine gas when passed through hot concentrated sodium hydroxide solution, disproportion reaction takes place to produce NaCl (oxidation state of Cl is -1 )and sodium chlorate with +5 oxidation state of chlorine.

3Cl_{2}+6NaOH \rightarrow 5NaCl + NaClO_{3}+3H_{2}O

(ii) When XeF_{6} is subjected to complete hydrolysis, the product formed is Xenon trioxide which is explosive and used as oxidizing agent.

XeF_{6}+3H_{2}O\rightarrow XeO_{3}+6HF

(iii) Concentrated sulphuric acid is a dehydrating agent and hence when added to cane sugar, dehydrates completely to generate a black carbon mass.

C_{12}H_{22}O_{11}\overset{conc. H_{2}SO_{4}}{\rightarrow}12C + 11H_{2}O

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