Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • (a) Explain why, for any charge configuration, the equipotential surface through a point is normal to the electric field at that point. Draw a sketch of equipotential surfaces due to a single charge (-q), depicting the electric field lines du

(a) Explain why, for any charge configuration, the equipotential surface through a point is normal to the electric field at that point.

Draw a sketch of equipotential surfaces due to a single charge (-q), depicting the electric field lines due to the charge.

(b) Obtain an expression for the work done to dissociate the system of three charges placed at the vertices of an equilateral triangle of side 'a' as shown below.

 

 

 
 
 
 
 

Answers (1)

Work  done to move a charge on the surface

dw=dq\left [ \vec{E}.\vec{dr} \right ]

But for an equipotential surface dw=0

dq\; Er\cos \theta =0

\Rightarrow \theta =90^{o}

i.e \vec{E}\perp \vec{dr}

Equipotential surface for -q

(b) Work done to dissociate the charge

w=-Potential\; energy

=\frac{-1}{4\pi \varepsilon _{o}}\left [ \frac{-4q^{2}}{a}+\frac{2q^{2}}{a}-\frac{8q^{2}}{a} \right ]

=\frac{10q^{2}}{4\pi \varepsilon _{o}a}

Posted by

Safeer PP

View full answer

Similar Questions

Latest Question