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(a) Explain why the intensity of light coming out of a polaroid does not change irrespective of the orientation of the pass axis of the polaroid.
(b) State, using a proper diagram, the condition when unpolarized light incident on the boundary between two transparent media produces polarised light, Explain briefly.
Hence show that the angle of incidence ' i_{\beta }' is related to the refiractive index \mu by the relation, \mu =\tan i_{\beta }.
 

 

 

 

 
 
 
 
 

Answers (1)

a) Unpolarised light has vibration in all direction. When unpolarised light passes through a polariser, the vibrations perpendicular to the polaroid are blocked.

Hence if polariser is rotated the unblocked vibrations remains same with axis of polariser. Hence the intensity of light does not change. For all position of polaroid half of the incident light get transmitted always.

b) When the refracted ray is perpendicular to reflected ray, the reflected light is completely plain polarised.

When i=i_{B}, r= 90-i_{B}

From snells law

\mu= \frac{\sin i_{B}}{\sin r}

= \frac{\sin i_{B}}{\sin (90-i_{B})}

= \frac{\sin i_{B}}{\cos i_{B}}

\mu= \tan i_{B}

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Safeer PP

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