Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A field is in a shape of a quadrilateral ABCD, in which AB= 18m, AD= 24m, BC= 40m, DC= 50m and angle A= 90 degree. Find the area of the field.

A field is in a shape of a quadrilateral ABCD, in which AB= 18m, AD= 24m, BC= 40m, DC= 50m and angle A= 90 degree. Find the area of the field.

Answers (1)

best_answer

Answer: 

The  quadrilateral ABCD is divided into two triangles . ABD and BCD.

⇒  ABD is a right angle triangle .

⇒ Area =( 1/2) (AB) (AD) as Angle A is 90 , 

⇒   Ab is the altitude and AD is the base = \ 1/2 imes 18 imes 24=216 

\ Rightarrow BC^2=AB^2+ AD^2Rightarrow BC=30

BCD triangle 

S = semi perimeter=60 

⇒ AREA = \sqrt60 imes 30 imes 20 imes 10=600

Total area=\816cm2

Posted by

Deependra Verma

View full answer

Similar Questions

Latest Question