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  • A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

Answers (1)

B has missed 27 times, this means that B has fired 2*27=54 shots.

As B fires 3 shots A fires 5 shots. Therefore when 54 shots are fired from B, A fires 54(5/3)=90.

A kills once in 3 shots then for 90 shots, A kills 90/3=30.

Posted by

Satyajeet Kumar

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