# A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be:

$Here\;in\;this\;case\;in\;identical\;contitions\;angle\;of\;elevation\;will\;be\; same\\* so,\theta =\phi\Rightarrow \tan\theta = \tan\phi\\* \tan\theta = \frac{17.5}{40.25}\;and\;\tan\phi =\frac{h}{28.75}\\* On,\; calculating \; we\;get\;h=12.5\;m\\* So,\;height\;of\;building\;is\;12.5\;m$

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