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(a) Give reasons :

     (i) H_3PO_3 undergoes disproportionation reaction but H_3PO_{4} does not.

     (ii) When Cl_{2} reacts with excess of F_{2} , ClF_{3} is formed and not FCl_{3}.

     (iii) Dioxygen is a gas while Sulphur is a solid at room temperature.

(b) Draw the structures of the following :
    (i) XeF_{4}

    (ii)HClO_{3}

 

 

 

 
 
 
 
 

Answers (1)

(a)

(i) H_3PO_3 undergoes disproportionation reaction but H_3PO_{4} does not. In H_3PO_{4}, the oxidation state of P is +5 therefore it can only get reduced but in H_3PO_{3}, it is +3 it can both get oxidized as well as reduced.

(ii) When Cl_{2} reacts with excess of F_{2} , ClF_{3} is formed and not FCl_{3} as chlorine has vaccant d-orbitals and can show oxidation state of +3 and due to high electronegativity and absence of d - orbitals in F, it cannot show oxidation state other than -1. Along with the bigger size, Cl can accomodate three F atoms.

(iii) Dioxygen is a gas while Sulphur is a solid at room temperature due to small size, 2p orbitals of oxygen can overlap effectively to form p\pi -p\pi multiple bonds. It exists as a gas due to weak Vander-Waals forces of attraction whereas sulphur have stronger Van-der waals forces exists as a Solid.

(b)

  (i) XeF_{4}

 

    (ii)HClO_{3}

Posted by

Sumit Saini

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