A heater coils of resistace 0.40 ohm carries a current I if the power of the power of the heater is 1kw calculate the magnitude of current and potenntial difference v

Answers (1)

given

i2R=1Kw

i2=1000/0.4 = 2500 

implies i = 50A

also

v2/R=1000w

v2=1000*0.4=400

therefore v= 20volt

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