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A heavy nucleus P of mass number 240 and binding energy 7.6 MeV per nucleon splits in to two nuclei Q and R of mass numbers 110, 130 and binding energy per nucleon 8.5 MeV and 8.4 MeV, respectively. Calculate the energy released in the fission.

 

 

Answers (1)

B.E. of heavy nucleus P =240\times7.6MeV=1824MeV

B.E. of heavy nucleus Q =110\times8.5MeV=135MeV

B.E. of heavy nucleus R =130\times8.4MeV=1092MeV

Energy released

=[(935 + 1092) − 1824] MeV
= [2027 − 1824] MeV
= 203 MeV

Posted by

Safeer PP

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