A house is fitted with 5 lamps of 60 watts, 6 lamps of 100 watts. if each lamp burns for 10 hours a day

Answers (1)

5 lamps of 60-watt burns for 10 hours. implies total KWh (units consumed) is

=\frac{5\times60\times10}{1000}KWh=3KWh

6 lamps of 100-watt burns for 10 hours. implies total KWh (units consumed) is

=\frac{6\times100\times10}{1000}KWh=6KWh

Total kWh consumed in a day = 6+3 = 9 KWh=9 units per day

For 30 days 270 units are consumed

1 rupee per unit, therefor for 270 units 270 rupees

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