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(a) How do you convert the following:

(i) Phenol to anisole

(ii)Ethanol to Propan-2-ol

(b)write the mechanism of the following reacion:

C_{2}H_{2}OH\xrightarrow[443K]{H_{2}SO_{4}}CH_{2}=CH_{2}+H_{2}O

(c)Why phenol undergoes electrophilic substitution reaction more easly than benzene?

 

 

 

 
 
 
 
 

Answers (1)

(a)(i)

    

(ii)

(b) C_{2}H_{2}OH\xrightarrow[443K]{H_{2}SO_{4}}CH_{2}=CH_{2}+H_{2}O

Mechanism:

Step 1: Formation of protonated alcohol.

Step 2: Formation of carbocation:

Steo 3: Elimination of a proton to form ethene.

H-CH_{2}-CH_{2}\rightleftharpoons CH_{2}=CH_{2}+H^{+}

(c) Phenols undergoes electrophilic substitution reactions due to the strong activating effect of -OH group aatached to benzene ring.

 

Posted by

Sumit Saini

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