(a) How do you convert the following:

(i) Phenol to anisole

(ii)Ethanol to Propan-2-ol

(b)write the mechanism of the following reacion:

C_{2}H_{2}OH\xrightarrow[443K]{H_{2}SO_{4}}CH_{2}=CH_{2}+H_{2}O

(c)Why phenol undergoes electrophilic substitution reaction more easly than benzene?

 

 

 

 
 
 
 
 

Answers (1)
S Sumit

(a)(i)

    

(ii)

(b) C_{2}H_{2}OH\xrightarrow[443K]{H_{2}SO_{4}}CH_{2}=CH_{2}+H_{2}O

Mechanism:

Step 1: Formation of protonated alcohol.

Step 2: Formation of carbocation:

Steo 3: Elimination of a proton to form ethene.

H-CH_{2}-CH_{2}\rightleftharpoons CH_{2}=CH_{2}+H^{+}

(c) Phenols undergoes electrophilic substitution reactions due to the strong activating effect of -OH group aatached to benzene ring.

 

Related Chapters

Preparation Products

Knockout NEET May 2021 (One Month)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 14000/- ₹ 6999/-
Buy Now
Foundation 2021 Class 10th Maths

Master Maths with "Foundation course for class 10th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
Buy Now
Foundation 2021 Class 9th Maths

Master Maths with "Foundation course for class 9th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
Buy Now
Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions