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(a)    Identify ‘A’ and ‘B’ in the following reaction:

        \xrightarrow {\textup{Sn} + \textup{HCl}} A\xrightarrow {\textup{Br}_2/\textup{H}_2\textup{O}} B

(b)    Why is ethylamine soluble in water whereas aniline is not?

 

 

 

 
 
 
 
 

Answers (1)

(a) 

   

                                                         Aniline                                 2,4,6-tribromoaniline

(b) Ethylamine is soluble in water due to the formation of hydrogen bonds with water but aniline is insoluble since the large hydrophobic phenyl group does not allow the formation of Hydrogen-bonds.

Posted by

Sumit Saini

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