Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A long straight wire AB carries a current of 3 A. A proton P travels at   parallel to the wire 0·3 m from it and in a direction o

A long straight wire AB carries a current of 3 A. A proton P travels at  5\times 10^{6}m/s parallel to the wire 0·3 m from it and in a direction opposite to the current as shown in the figure. Calculate the force which the magnetic field due to the current carrying wire exerts on the proton. Also give its direction. 

 

 
 
 

Answers (1)

Given that, 

  r=0.3m

Current  I=3A

Speed of proton = 5\times 10^{6}m/s

The magnetic field produced by long wire AB at the point P is 

B=\frac{\mu_0I}{2\pi r}   

Proton is moving in perpendicular to the magnetic field so the magnetic force is 

F_m=qvB

Then,

B=\frac{\mu _0I}{2\pi r}=\frac{4\pi \times 10^7\times 3}{2\times \pi \times 0. 3}=2\times 10^{-6}T

So, 

F_m=qvB

        =1.6\times 10^{-19}\times 5\times 10^6\times 2\times 10^{-6}

        =1.6\times 10^{-18}N

By fleming's left-hand rule, the direction of force is away from the long wire AB towards the right.

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years
anam-khan

CBSE Class 12 accountancy board exam analysis 2024 out; paper rated easy, balanced

Latest Question