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  • (a) Obtain the expression for the deflecting torque acting on the current carrying rectangular coil of a galvanometer in a uniform magnetic field. Why is a radial magnetic field employed in the moving coil galvanometer ? (b) Particles

(a) Obtain the expression for the deflecting torque acting on the current carrying rectangular coil of a galvanometer in a uniform
magnetic field. Why is a radial magnetic field employed in the moving coil galvanometer ?

(b) Particles of mass 1.6\times 10^{-27}kg and charge1.6\times 10^{-19}C are accelerated in a cyclotron of dee radius 40 cm. It employs a magnetic field 0.4 \; T. Find the kinetic energy (in MeV) of the particle beam imparted by the accelerator.

 

 

 

 

 
 
 
 
 

Answers (1)

a) Let us consider a loop ABCD in a uniform magnetic field of strength B. and Let the current through the loop be I.

Magnetic forces of AB and CD are equal and opposite and have
a different line of action so constitutes torque.

\tau=F\timesthe perpendicular distance between two force arm
\tau=NBilbsin\theta (if the coil has N turns)
lb=A
\tau=NiABsin\theta=M XB

Galvanometer has Radial magnetic field to increase the field strength and to make torque independent of orientation. Also, the radial magnetic field gives the maximum torque.

b) 

\\KE=\frac{1}{2}\frac{q^2B^2R^2}{m}\\\\=\frac{1}{2}\frac{(1.6\times10^{-19})^2\times(0.4)^2\times(0.4)^2}{1.6\times10^{-27}\times1.6\times10^{-19}}eV\\\\=1.28MeV

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Safeer PP

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