(a) Plot a graph to show the variation of stopping potential with frequency of incident radiation in relation to photoelectric effect.

(b) Use Einstein’s photoelectric equation to show how from this graph,

(i) Threshold frequency, and

(ii) Planck’s constant can be determined.

 

 

 

 
 
 
 
 

Answers (1)
S safeer

(a) Due to the increase in frequency, there is an increase in kinetic energy of the electron.

So, the stopping potential increases with increase in the frequency of incident radiation in relation to the photoelectric effect.

(b) 

eV_{o}=h\nu -h\nu _{o}

V _{o}=\frac{h}{e} (\nu -\nu _{o})

Point p on the graph shows the threshold frequency.

e\nu _{o}=h\nu -\phi _{o}

\nu _{o}=\frac{h}{e}\nu -\frac{\phi _{o}}{e}

Hence, the threshold frequency \nu _{o} is the intercept along \nu(frequency) axis.

Now, the slope of the given graphs gives \frac{h}{e} 

slope=\frac{h}{e}

Hence, plank's constant h=e\times \ slpoe slope of the graph   

Preparation Products

Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Test Series NEET May 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions