(a) Plot a graph to show the variation of stopping potential with frequency of incident radiation in relation to photoelectric effect.

(b) Use Einstein’s photoelectric equation to show how from this graph,

(i) Threshold frequency, and

(ii) Planck’s constant can be determined.

 

 

 

 
 
 
 
 

Answers (1)

(a) Due to the increase in frequency, there is an increase in kinetic energy of the electron.

So, the stopping potential increases with increase in the frequency of incident radiation in relation to the photoelectric effect.

(b) 

eV_{o}=h\nu -h\nu _{o}

V _{o}=\frac{h}{e} (\nu -\nu _{o})

Point p on the graph shows the threshold frequency.

e\nu _{o}=h\nu -\phi _{o}

\nu _{o}=\frac{h}{e}\nu -\frac{\phi _{o}}{e}

Hence, the threshold frequency \nu _{o} is the intercept along \nu(frequency) axis.

Now, the slope of the given graphs gives \frac{h}{e} 

slope=\frac{h}{e}

Hence, plank's constant h=e\times \ slpoe slope of the graph   

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