Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A resistance and a capacitor are connected in series to a source <img alt="V=V_{0}\sin \omega t" src="https://lea

A resistance R and a capacitor C are connected in series to a source
V=V_{0}\sin \omega t.
Find :

(a) The peak value of the voltage across the (i) resistance and (ii) capacitor.

(b) The phase difference between the applied voltage and current. Which of them is ahead ?

 

 

 
 
 
 
 

Answers (1)

a) The peak value of the current through the circuit

I_0=V_0/Z=\frac{V_0}{\sqrt{R^2+X_C^2}}

i)

V_R=I_0R=\frac{V_0R}{\sqrt{R^2+X_C^2}}

ii)

V_C=I_0X_C=\frac{V_0X_C}{\sqrt{R^2+X_C^2}}

The phase difference between applied voltage and current

\phi=tan^{-1}(\frac{X_C}{R})

In RC series circuit the current leads the applied voltage 

 

 

 

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Result 2025 Live: UK Board 10th, 12th results tomorrow; AP SSC, TS Inter, UP, CBSE updates
anam-khan

When will CBSE Class 12 results 2025 be declared? Last two years' trends
anam-khan

CBSE Class 10, 12 board exams 2025 from April 7 to 11 for sports students

Latest Question