A resistor R and an inductor L are connected in series to a source of voltageV = V_o \sin \omega t. The voltage is found to lead current in phase by \frac{\pi}{4}. If the inductor is replaced by a capacitor C, the voltage lags behind current in phase by \frac{\pi}{4}. When L, C and R are connected in series with the same source,

Find the :

(i) average power dissipated and

(ii) instantaneous current in the circuit.

 

 

 
 
 
 
 

Answers (1)

i)

\\P_{avg}=I_{eff}\times V_{eff}\times cos0=I_{eff}^2R\\\\=\frac{V_0^2}{R}

ii) 

Instantaneous current. 

I=V/R

\frac{V_0}{R}sin wt=I_0 sinwt

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