A small flat search coil of area 5cm^{2} with 140 closely wound turns is placed between the poles of a powerful magnet producing magnetic field 0.09\; T and then quickly removed out of the field region. Calculate

(a) change of magnetic flux through the coil, and

(b) emf induced in the coil.

 

 
 
 
 
 

Answers (1)
S safeer

(a) The change of magnetic flux through the coil will be given as :

\Delta \phi =\phi _{2}-\phi _{1}

\Delta \phi =0-\phi _{1}\; \; \; (\because \phi _{2}=0)

\Delta \phi =0-NBA\cos \theta

Where, N = 140 = number of turns

            B = 0.09 = magnetic field

            A = S = Area

Then,

\Delta \phi =-140\times 0.09\times5\times 10^{-4}\cos \theta

\Delta \phi =-63\times 10^{-4}wb

(b) Now, calculating the induced emf of the coil is given as ;

e=\frac{-\Delta \phi }{\Delta t}

e=\frac{63\times 10^{-4}}{\Delta t}V

Assuming coil is removed within a millisecond

e=\frac{63\times 10^{-4}}{10^{-3}}V=6.3V

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