Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A small seminar hall can hold 100 chairs. Three different colours (red, blue and green) of chairs are available. The cost of a red chair is Rs.240, cost of a blue chair is Rs.260 and the cost of a green chair is Rs.300. The total cost of chair is Rs.25,00

A small seminar hall can hold 100 chairs. Three different colours (red, blue and green) of chairs are available. The cost of a red chair is Rs.240, cost of a blue chair is Rs.260 and the cost of a green chair is Rs.300. The total cost of chair is Rs.25,000. Find atleast 3 different solution of the number of chairs in each colour to be purchased.

Answers (1)

best_answer

Let;the;number;of;red,blue;and;green;chairs;be;x,y;and;z respectiv ely.\*total;number;of;chairs=100\*x+y+z=100;;;;;;..eq(1)\*According;to;question,\*240x+260y+300z=25000Rightarrow 12x+13y+15z=1250 ;;;;;eq(2)\*From;..eq(1)Rightarrow x+y =100-z\* From;..eq(2) Rightarrow 12x+13y=1250-15z\*take;z=k;where;k;is;an;arbitrary; constant;and;is;a;real;number\*so;the; above;equations;become\* x+y=100-k\* 12x+13y=1250-15k\*put; x,y=1\*|12-13|=1 eq 0\*by; cramers;rule;the;equations;have;a; unique;solution.\*replace;the; first;column;in;the;determinant;by; 100 -k;and;1250-15k\* Rightarrow 1300-13k-1250+15k=2k+50/1= 2k+50 =x\*now,;replace;the ;second;column;in;the;determinant;by;100-k; and ;1250-15k\*1250-15k-(12)(100-k)=1250-15k-1200+12k=50-3y=y\*Now, z=k\*k;lie; betwe en;0;and;16;since;50-3k;should; not; acquire;a; negative;value\* k=0,1,2;in;(2k+50,50-3k,k);then;(50,50,0),(52,47,1),(54,44,2); respectively

Posted by

Deependra Verma

View full answer

Similar Questions

Latest Question