Get Answers to all your Questions

header-bg qa

A solid is in the shape of a hemisphere surmounted by a cone. If the radius of hemisphere and base radius of cone is 7 cm and height of cone is 3.5 cm, find the volume of the solid. (Take \pi =\frac{22}{7})

 

Answers (1)

\\$ Given:Radius of the cone = Radius of the hemisphere $=r=7 \mathrm{cm} \\ $ Height of cone = 3.5 \mathrm{cm}$ \\ $Volume of solid = volume of cone + volume of hemisphere

\\=\frac{1}{3} \pi r^{2} h+\frac{2}{3} \pi r^{3} \\ =\frac{1}{3} \pi r^2( h+2 r) \\ =\frac{1}{3} \times \frac{22}{7} \times 7^2( 3.5+14) \\ =\frac{1}{3} \times \frac{22}{7} \times 7^2( 17.5) \\ $ = 898.33 $cm^3

Posted by

Safeer PP

View full answer