A sphere increses its volume at the rate of pi cc/sec. The rate at which its surface area increses when the radius is 1 cm is .

Answers (1)

Solution:   

                 V=frac43pi r^3

                 S=4pi r^2

                                fracmathrmd Vmathrmd t=4pi r^2fracmathrmd rmathrmd tRightarrow pi=4picdot 1(fracmathrmd rmathrmd t)

               Or               fracmathrmd rmathrmd t=frac14

             	herefore            fracmathrmd Smathrmd t=4picdot 2r(fracmathrmd rmathrmd t)=2pi  sq cm/s.

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