A square shaped current carrying loop MNOP is placed near a straight long current carrying wire AB as shown in the fig. The wire and the loop lie in the same plane. If the loop experiences a net force F towards the wire, find the magnitude of the force on the side ‘NO’ of the loop.

 

 

 
 
 
 
 

Answers (1)

Force on MN and OP cancels each other. 

F_{NO}=\frac{1}{2}F_{MP}

\\F=F_{MP}-F_{NO}=F_{MP}-\frac{1}{2}F_{MP}\\=\frac{1}{2}F_{MP}

Therefore

\\F=F_{NO}

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