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(a) The potential difference applied across a given resistor is altered so that the heat produced per second increases by a factor of 9. By what factor does the applied potential difference change?

(b) In the figure shown, an ammeter A and a resistor of 4 \Omega are connected to the terminals of the source. The emf of the source is
12 V having an internal resistance of 2 \Omega . Calculate the voltmeter and ammeter readings.

 

 
 
 
 
 

Answers (1)

a) We know that heat produced

H=\frac{V^{2}}{R}t

given

H^{1}=9H

Here t=1\; sec

         R=Constant

to find V'

\frac{V'^{2}}{R}\times 1=9\frac{V^{2}}{R}\times 1

\Rightarrow V'=3\; V

Thus the applied potential difference change by a factor of 3

b) The total current through the circuit

I = \frac{12}{4+2}=2A

Reading of the voltmeter is

12-2\times I

=12-4

  =8 V

Posted by

Safeer PP

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