Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A thin metallic spherical shell of radius R carries a charge Q on its surface. A point charge is placed at the centre C and another charge <img alt="+2Q" src="https://entran

A thin metallic spherical shell of radius R carries a charge Q on its surface. A point charge Q/2 is placed at the centre C and another charge +2Q is placed outside the shell at A at a distance x from the centre as shown in the figure.
(i) A Find the electric flux through the shell.
(ii) State the law used.
(iii) Find the force on the charges at the centre C of the shell and at the point A

 

 
 
 
 
 

Answers (1)

(i) The electric flux through the shell is zero since the electric field inside the shell is zero.

(ii) Gauss Law; The total electric flux through a closed surface enclosing charge q is \frac{1}{\varepsilon _{0}} times the total charge q enclosed by the surface.

\phi =\oint E.dA=\frac{1}{\varepsilon _{0}}q

(iii) At point C electric field =0, therefore force =0

At A

The net charge on the shell

=Q+\frac{Q}{2}=\frac{3Q}{2}

The electric field at A due shell

=\frac{K\frac{3Q}{2}}{x^{2}}

and force at A

F=E\times 2Q

=\frac{K\frac{3Q\times 2Q}{2}}{x^{2}}

F=\frac{3Q^{2}}{4\pi \varepsilon _{0}r^{2}}

Posted by

Safeer PP

View full answer

Similar Questions

Latest Question